3 years ago

Two hundred eight thousand five hundred sixty one in standard form

1 answer:

8 0

28,561 should be the correct answer

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Goryan [66]

Answer:

Step-by-step explanation:

The given expression is

$\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}$

Recall and use

$a^m\times a^n=a^{m+n}$

$\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}$

$\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}$

Same bases are dividing, so we write one base and subtract the exponent.

$2^{-\frac{13}{2}+\frac{13}{2}}$

$2^0=1$

8 0

3 years ago

blagie [28]

The median may stay the same.

The range will always change.

I dont think the last 2 will always change.

7 0

3 years ago

katovenus [111]

0....1/4..... 2/4 or 1/2 ..... 3/4..... 1.... 1 1/4.... 1 2/4 or 1 1/2...... 1 3/4..... 2.... and so on and so on

8 0

3 years ago

allsm [11]

4x-10 and 7x-8 are supplementary angles and thus add up to 180 degrees.

Thus, 11x - 18 = 180 degrees.

Combining like terms, 11x = 198, and x = 18.

The two supplementary angles are 4(18)-10 and 7(18)-8, or 62 and 118 degrees.

4 0

3 years ago

quester [9]

Sorry I have no idea

4 0

3 years ago