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balandron [24]
3 years ago
11

Help ?? (Pls don’t answer unless you know)

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:  \boldsymbol{\left(x, \frac{2}{3}x-1\right)}

This is the same as writing ( x, (2/3)x-1 )

============================================================

Explanation:

The red and green lines are identical. They are drawn very <em>slightly</em> apart so the reader can spot the difference (you'll have to look really closely).

Because both lines are identical, this means we have infinitely many solutions. The two lines intersect at infinitely many locations. Each solution is on that line.

Your teacher wants you to find the equation of this line so you can write all solutions of the form (x, mx+b).

---------

The red line goes through (0,-1) and (3,1). Let's find the slope of this line

m = (y2-y1)/(x2-x1)

m = (1-(-1))/(3-0)

m = (1+1)/(3-0)

m = 2/3

The y intercept is b = -1 because the red line crosses the y axis at this location.

So we go from y = mx+b to y = \frac{2}{3}x-1 to represent the equation of both red and green lines.

Any (x,y) solution on this line is of the form \left(x, \frac{2}{3}x-1\right) since we replace y with \frac{2}{3}x-1

To write \left(x, \frac{2}{3}x-1\right) on a keyboard, you can type ( x, (2/3)x-1 )

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20 % of 2 is equal to <br><br> A. 20 <br> B. 4 <br> C. 0.4 <br> D. 0.04
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Someone please help!!! Due tonight, I’ll give brainliest!!!
Ad libitum [116K]

Answer:

2 * 0.75 + 0.50 + 4 * 1.25

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2 * 0.75 + 0.50 + 4 * 1.25

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3 years ago
A restaurant has an electronic system that randomly selects customers when they pay for their meal to
polet [3.4K]

Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • For each customer, 10% probability of receiving a coupon, thus p = 0.1.
  • 2 customers are selected, thus n = 2

The probability that <u>neither receives a coupon is P(X = 0)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.1)^{0}.(0.9)^{2} = 0.81

0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

A similar problem is given at brainly.com/question/25326823

7 0
3 years ago
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