Answer:
14 ; three of them are black, 2 are black and leather, 9 are leather
Step-by-step explanation:
i hope this helps
39% as a ratio would be 39:100. Since percents are over of a hundred it would be 39:100 or 39/100.
Answer:
In quadrant 1
Step-by-step explanation:
Quadrant 1 is (positive, positive) which falls in the category (10,25)
Answer:
Sample = The 5 cows selected by the farmer.
Population = all of the farmer's dairy cows
Statistic = The five measurements collected on cows selected by the farmer.
Data = Variance in daily milk production among the cows in the farmer's sample
Parameter = a quantity equivalent to the volume of milk produced by a randomly selected cow
Step-by-step explanation:
Population refers to all members belonging to a particular group of interest ; all the farmer's dairy cows
Sample : A small subset of observation selected from the sample; 5 selected cows from the population.
Statistic: Numeric characteristic of the observations derived from the sample
Parameter : Numeric characteristic of observation derived from the population.
Data: gathered figures calculated from either sample or population ; the variance in Daily milk production.
![A=\left[\begin{array}{ccc}3&-2\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-2%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
We can find the A as shown below:
Given A^2=I
We know that A^2=A×A
And ![I=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
So, ![A^2=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Let ![A=\left[\begin{array}{ccc}3&-2\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-2%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
![A^2=\left[\begin{array}{ccc}3&-2\\4&-3\end{array}\right] \left[\begin{array}{ccc}3&-2\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-2%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-2%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
![A^2=\left[\begin{array}{ccc}9-8&-6+6\\12-12&-8+9\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9-8%26-6%2B6%5C%5C12-12%26-8%2B9%5Cend%7Barray%7D%5Cright%5D)
![A^2=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Hence, ![A=\left[\begin{array}{ccc}3&-2\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-2%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
Hence, option C is correct
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