Question

Check all that apply, if csc theta=13/5, then:

Answer 1

csc θ = 13/5

$\frac{1}{sin. theta} = \frac{13}{5}$

When you flip both sides:

sin θ = 5/13

If you know the Pythagorean triples, it will be 5, 12, and 13. Otherwise you could do a² + b² = c²

You can use:

$S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}$

which is

$Sin \frac{opposite}{hypotenuse} Cos\frac{adjacent}{hypotenuse} Tan\frac{opposite}{adjacent}$

Or you could draw a triangle, either way works.

To find tangent, you know 13 is the hypotenuse because it is the longest side, and 5 is "opposite" so 12 is "adjacent. So:

tan theta = 5/12

And cosine is adjacent/ hypotenuse, so it is:

cos theta = 12/13

sec theta is the opposite of cos theta, so it is:

sec theta = 13/12

B and C are correct