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marta [7]
3 years ago
12

The radius of the circle-shaped is 9 inches. What is the approximate circumference? (Use 3.14 for

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

56.5

Step-by-step explanation:

circumfrence is 2 pi R

If the radius is 9=R

then the circumfrence is 56.5

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Select the graph of the solution set that would represent the following expression. (x-2)=5(x+1)​
Lesechka [4]

Answer:

Find the attached

Step-by-step explanation:

We have been given the following expression;

(x-2)=5(x+1)

We are required to determine the graph of the solution set. To do this we formulate the following set of equations;

y = x - 2

y = 5(x+1)

We then graph these two equations on the same cartesian plane. The solution will be the point where these two graphs intersect.

Find the attachment below;

5 0
3 years ago
Read 2 more answers
Pls help. Will mark for CORRECT ANSWER!!
Travka [436]
Y = mx + b
slope(m) = -4
(-2,5)....x = -2 and y = 5
now we sub into the formula and find b, the y int
5 = -4(-2) + b
5 = 8 + b
5 - 8 = b
-3 = b

so ur equation is : y = -4x - 3 <==
3 0
3 years ago
The following data is from a simple random sample of 12 students GPAs. 3.12 2.45 4.0 3.76 3.54 2.78 3.39 3.21 1.98 3.43 3.98 2.7
Rufina [12.5K]

Answer: 3. 2

Step-by-step explanation:

Given the data:

3.12 2.45 4.0 3.76 3.54 2.78 3.39 3.21 1.98 3.43 3.98 2.77

Point estimate of population mean :

Σx / N

(3.12 + 2.45 + 4.0 + 3.76+ 3.54 + 2.78 + 3.39 + 3.21 + 1.98 + 3.43 + 3.98 + 2.77)

= 38.41 / 12

= 3.2008

4 0
3 years ago
Find the sum and express it in simplest form (-b-5x-3)+(2b-4x+7)
vovikov84 [41]
-b - 5x - 3 + 2b - 4x + 7....combine like terms
b - 9x + 4 <==
6 0
3 years ago
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The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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