2(m + 9) = 24 find m

What is 658 divided by 72?

SIZIF [17.4K]

Answer:

9.13889

Step-by-step explanation:

.........................

8 0

3 years ago

Read 2 more answers

Julia is opening a clothing store. She plans to start by selling sweatshirts. if it costs her $9.50 for each sweatshirt, $5 for

Lilit [14]

B is definatly the correct answer, Add all of the prices, and that is what it costs per sweatshirt

7 0

3 years ago

The table shows linear relashonsips between x and y write an equation in slope intercept form for this relashonsip!!!!!!!!!!!!!!

Alchen [17]

Answer:

$y=-2x+6$

Step-by-step explanation:

Slope-intercept form is given as $y=mx+b$ , where $m$ is slope and $b$ is the y-intercept.

To find the slope of a line that passes through two points $(x_1, x_2)$ and $(y_1, y_2)$ , use the slope formula:

$m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}$

Let:

$(x_1, y_1)\implies (1, 4)\\(x_2, y_2)\implies (0, 6)$

The slope of the line that passes through these two points is:

$m=\frac{6-4}{0-1}=\frac{2}{-1}=-2$

Now substitute $m=-2$ and any point to solve for $b$ :

$y=mx+b,\\6=-2(0)+b,\\6=0+b,\\b=6$

Therefore, the slope-intercept form of a line that is represented by the table is $\boxed{y=-2x+6}$

8 0

3 years ago

If sin theta = 2/5 and theta is in quadrant I, determine the following.

anzhelika [568]

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=\stackrel{hypotenuse}{5}\\ a=adjacent\\ b=\stackrel{opposite}{2}\\ \end{cases} \\\\\\ \pm\sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a\implies \stackrel{I~Quadrant}{+\sqrt{21}=a}$

recall that cosine is positive on the I Quadrant, so though we get a ± valid roots, only the positive one applies.

$\bf cos(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{hypotenuse}{5}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}} \qquad \qquad cot(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{opposite}{2}} \\\\\\ csc(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{opposite}{2}} \qquad \qquad sec(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}$

now, for tangent and secant, let's rationalize the denominator.

$\bf tan(\theta)\implies \cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{21} \\\\\\ sec(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{5\sqrt{21}}{21}$

5 0

3 years ago

Simplify (1+ V3) (2-3).

Harrizon [31]

Answer: -1-3V
Explanation:

7 0

4 years ago