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Lostsunrise [7]
3 years ago
13

What are the foci of the hyperbola whose equation is

Mathematics
2 answers:
motikmotik3 years ago
5 0

Answer:

(4,12) (4,-8)

Step-by-step explanation:

you can find the distance from the foci to the center of a hyperbola using the formula c2 = a2 + b2.

in this equation we have both a and b, so substitute the values into the equation...

c2 = 64 + 36

c2 = 100

square root

c=10

therefore the distance from the foci from the center is 10 units.

since the equation has the y term first, the transverse axis is vertical. so 10 y  units from the center which is (4,2) is (4,12) and (4,-8)

making the answer be (4,12) and (4,-8).

Hope this helped :)

makkiz [27]3 years ago
4 0
I think the answer is D
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Which expression is equivalent to 4 (3n - 5)?
mart [117]

Expression 4 (3n - 5) is equivalent to <em><u>C: 12n - 20</u></em>

<h3>Further explanation </h3>

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

  • 1. phrases

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

  • 2. variable

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

  • 3. constants

is a fixed value, can be a number

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There are several properties in integer multiplication operations

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Multiplication between integers will produce integers too

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*<em> addition </em>

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* <em>substraction </em>

ax (b-c) = axb - axc

We can use distributive  property  of <em>substraction   </em>to solve the problem

\displaystyle =4(3n-5)\\\\=4x3n - 4x5\\\\=12n-20

"Equivalent to" means having the same value.

From the answer choices , which produce the same expression is C. 12n-20

<h3>Learn more </h3>

6 squared divided by 2 (3) +4

brainly.com/question/376058

an algebraic expression

brainly.com/question/20988

brainly.com/question/2285423

Keywords: PEMDAS, arithmetic operations, multiply, Parentheses, equivalent to

5 0
4 years ago
Read 2 more answers
This is a System Of Equations and I'd like it to get solved by the Elimination or Substitution Method.x+2y=83x+5y=8
Sonbull [250]

Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.

x + 2y = 83    &    x + 5y = 8

Solve for x.

x = 83 - 2y     &    x = 8 - 5y

Once you have solved for x, set each equation equal to one another and solve for y now.

83 - 2y = 8 - 5y

Isolate all variables to one side:

83 = 8 - 3y

Now subtract the 8 to fully isolate the y variable:

75 = -3y

Divide by -3:

-25 = y   Now that you have your first variable, plug it into one of the original equations and solve for x.

x + 2(-25) = 83

x - 50 = 83

x = 133

Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

Put each equation on top of one another and subtract:

  x + 2y = 83

- (x + 5y = 8)

The x's will cancel out:

(x - x) + (2y - 5y) = (83 - 8)

Simplify:

-3y = 75

Solve for y

y = -25

Then, plug y = -25 into one of the original equations:

x + 5(-25) = 8

Solve for x:

x - 125 = 8

x = 133

Hope this helps!

8 0
3 years ago
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