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Lina20 [59]
3 years ago
12

Which system has no solutions?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0
\left\{\begin{array}{ccc}y \ \textgreater \  6\\y \ \textless \  2\end{array}\right\\\\\text{Look at the picture}

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A bicyclist goes 43.54 miles in 3.5 hours. What is her speed?
Studentka2010 [4]
Divide 43.54 by 3.5
She was going 12.33 miles an hour
6 0
3 years ago
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Simplify. (3m^2n4)^3 <br>A)27m^5n^7 <br>B)9m^6n12 <br>C)27m^6n^12<br>D)9m^5n^7
butalik [34]
(3m²n⁴)³ = 27m^6n^12. choice C
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3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
2 years ago
Could anyone help me with this problem i'm stuck <br><br> h(17)= ?
nikdorinn [45]

Answer:

\sqrt{17t}

Step-by-step explanation:

Consider the right side of the table

It informs us of the values for h(t) for different values of t

The top one informs us what h(t) is when t = 17, that is

h(t) = \sqrt{17t}, when t = 17, thus

h(17) = \sqrt{17t}

4 0
3 years ago
Someone help,please.I don't understand very well.
Setler79 [48]
You just add THAM All up
8 0
3 years ago
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