All categories

3 years ago

Order each set of numbers from least to greatest 0.48, 0,46, 9/20

Mathematics

2 answers:

laiz [17]3 years ago

6 0

9/20 = .45

9/20, .46, .48

ki77a [65]3 years ago

3 0

1. 9/20 = 0.45

2. 0.46

3. 0.48

You might be interested in

Mrs. Kato has 6 bags of dried beans and a 2-pound bag of rice in one shopping bag. In another shopping bag she has a 5-pound bag

Serjik [45]

Given:

Mrs. Kato has 6 bags of dried beans and a 2-pound bag of rice in one shopping bag.

In another shopping bag she has a 5-pound bag of flour.

The two shopping bags weigh the same amount.

To find:

The weight of each bag of dried beans.

Solution:

Let x be the weight of each bag of dried beans.

So, weight of 6 bags of dried beans = 6x.

According to the question,

Weight of first bag = (6x + 2) pounds

Weight of second bag = 5 pounds

The two shopping bags weigh the same amount. So,

$6x+2=5$

$6x=5-2$

$6x=3$

Divide both sides by 6.

$x=\dfrac{3}{6}$

$x=0.5$

Therefore, the weight of each bag of dried beans is 0.5 pounds.

5 0

3 years ago

Could someone help with my previously asked questions

m_a_m_a [10]

Answer:

ill try! <3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

he Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and

sergejj [24]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

$H_0:$ Management quality and corporate reputation are independent.

$H_1:$ Management quality and corporate reputation are not independent.

Test statistic:

$\to \chi^2 = \frac{\sum (O-E)^2}{E}$

$= 0.71429 + 0.0102 +2.8809+0.625+1.75 +0.3333 +0+3.2143+7.5\\\\= 17.02806$

The critical $\chi^2$ for $df = (r-1)(c-1) = (3-1)(3-1)= 4$ and $\alpha = 0.05$ is $\chi^2= 9.4877$

Test statistic:

$17.02806 > 9.4877$ therefore rejecting the null hypothesis $H_0$ .

p-value $= 0.001909$

Interpretation:

There is no internal governance quality as well as the reputation of the organization.

3 0

3 years ago

Calculate the total surface area of a pipe with inner surface area 1508.5 square cm, outer surface area 2514.2 square cm, and in

algol [13]

Answer:

The total surface area of the pipe is 4123.31 cm²

Step-by-step explanation:

Total surface area (TSA) of a pipe is calculated as;

Outer area of the pipe + Inner area of the pipe + cross section of the two ends

TSA = 2πRL + 2πrL + 2π(R² - r²)

TSA = 2π(RL + rL + R² - r²)

where;

R is the outer radius

r is the inner radius

L is length of the pipe

Determine the length of the pipe

Outer surface area of the pipe is calculated as;

outer surface of the pipe = 2πRL

2514.2 = 2πRL

2514.2 = (2π x 5) L

2514.2 = 31.42 L

L = 2514.2 / 31.42

L = 80.02 cm

Finally, determine the total surface area of the pipe

TSA = 2π(RL + rL + R² - r²)

TSA = 2π(5x80.02 + 3x80.02 + 5² - 3²)

TSA = 2π(400.1 + 240.06 + 16)

TSA = 2π(656.16)

TSA = 4123.31 cm²

Therefore, the total surface area of the pipe is 4123.31 cm²

8 0

4 years ago

If the sum of a number and one is tripled, the result is four less than twice the number. Find the number.

vagabundo [1.1K]

x+1*3+y-4=x

the answer

8 0

3 years ago