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3 years ago

Order each set of numbers from least to greatest 0.48, 0,46, 9/20

Mathematics

2 answers:

laiz [17]3 years ago

6 0

9/20 = .45

9/20, .46, .48

ki77a [65]3 years ago

3 0

1. 9/20 = 0.45

2. 0.46

3. 0.48

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Evaluate................

wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0

3 years ago

Solve for x -9<4x+3<27 enter your answer as one inequality in the box

ludmilkaskok [199]

If a< c< b then a<c and c<b

Separate the equation into 2 separate ones and solve them:

X-9 < 4x +3

Subtract 3 from both sides:

X-12 < 4x

Subtract x from both sides:

-12< 3x

Divide both sides by 3:

X > -4

4x+3 < 27

Subtract 3 from both sides

4x < 24

Divide both sides by 4

X <6

Combine to get one inequality:

-4<x<6

6 0

3 years ago

the line containing the altitude to the hypotenuse of a right triangle whose vertices are p(-1, 1), q(3, 5), and r(5, -5).

finlep [7]

The equation of the straight line is given by 5y-x=6

An equation can be used to describe a straight line drawn on the Cartesian Plane. These equations have a generic structure and can change based on the slope and where the line intersects the axes.

We will greatly simplify this issue by utilizing the fact that this triangle is specified as a right triangle. We would have had to establish the presence of a right angle if it had been presented as a general triangle.

The segment QR is the hypotenuse of the triangle.

Any side's altitude is located along a line that is perpendicular to that side. We are aware that the slopes of perpendicular lines are negative reciprocals, or:

Slope of line joining Q(3, 5) and R(5, -5)

m= $\frac{y_2-y_1}{x_2-x_1}$