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Scrat [10]
3 years ago
15

For which of the following inequalities is x greater than or equal to 4 a solution?

Mathematics
1 answer:
telo118 [61]3 years ago
4 0
Either a or b. Depends on what X equals. For example, question a.- X+3, it has to be at least 1. Answer b- 3X, has to be a little over 2. So I guess the most correct answer has to be A.
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4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2
Anna007 [38]

Answer:

<u>Given data:</u>

  • 4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2

<u>Put the data in the ascending order:</u>

  • 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6, 8

<u>Mean, the average:</u>

  • (1 + 2*5 + 3*4 + 4*4 + 5*2 + 6 + 8)/18 = 3.5

<u>Median, average of middle two numbers:</u>

  • 3

<u>Mode, the most repeated number:</u>

  • 2 (repeated 5 times)

Mean is normally the best measure of central tendency, same applies to this data.

6 0
3 years ago
Read 2 more answers
Write an inequality that represents the verbal expression. 9 less than a number n is less than 17.
bekas [8.4K]
9>n>17
it means that n can be whatever number between 9 and 17
7 0
4 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
4 years ago
Whats 23x+34=x<br> u ain't r e a l l y got tu
MatroZZZ [7]

Answer:

x= -17/11

Step-by-step explanation:

7 0
3 years ago
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Help with geometry will mark brainliest for correct anwsers
Veseljchak [2.6K]
The first one is (-2,1)
The other one is 36
4 0
3 years ago
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