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Ymorist [56]
3 years ago
6

Exponential functions have the form f(x)=b^x. What type of an exponential function would you have (increasing or decreasing) if

the value of b is greater than one?

Mathematics
1 answer:
adoni [48]3 years ago
8 0

Answer:

Increasing

Step-by-step explanation:

Let's see what happens if we choose a value for b greater than 1.

Let's try b=2.

f(x)=2^x.

I'm going to keep increasing x. If y increases, the the function is increasing. If y decreases, the function is decreasing.

Let's start with x=1.

y=2^1=2

Now x=2.

y=2^2=4

The y's got higher as you increased x so the function is increasing.

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Find the slope of the line (-3,-2) (1,6)
nlexa [21]

Answer:

slope = 2

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 3, - 2) and (x₂, y₂ ) = (1, 6)

m = \frac{6-(-2)}{1-(-3)} = \frac{6+2}{1+3} = \frac{8}{4} = 2

5 0
3 years ago
the gasoline gauge on a van initially read 1/8 full. When 15 gallons were added to the tank, the gauge read 3/4 full. how many m
nexus9112 [7]
Let x be the capacity of the tank then
3x/4-x/8 =15,
then x=24, so so far it has 3/4 *24 =18 so you need 6 gallons to fill it up
5 0
3 years ago
How do I find the answer?
11Alexandr11 [23.1K]
First simplify the number part, 14/2 = 7/1
then the x part, \frac{x}{x^ \frac{3}{4} } = x^ \frac{1}{4} 

y doesn't need to be simplified
then simplify the z part, z^-6 = z^6

put it all together...
7x^ \frac{1}{4}y^ \frac{1}{3} z^6
4 0
3 years ago
Emma receives $7750 and invests it in an account that earns 4% interest copounded continuously, What is the total amount of her
QveST [7]
So your present value is 7750. this is what you have now. they give you the intesrest rate which is 4% and how the amount of year is 5.

recall the formula for a compounded continously is
P×e^(r×t)

the answer is 7750×e^(.04×5)
8 0
2 years ago
The table represents an exponential function. What is the multiplicative rate of change of the function? X, 1,2,3,4 Y, 6,4,8/3,1
Vsevolod [243]
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6 0
3 years ago
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