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Westkost [7]
3 years ago
12

Compute the total work and power output per minute for 10 minutes of

Biology
1 answer:
Leona [35]3 years ago
8 0

Answer:

Work = 92,704.5 joules

Power= 154.5 watts

Explanation:

Given that:

Time= 10 minutes

treadmill grade = 15% = 0.15

horizontal speed = 90 meters/min

subjects weight = 70 kg

To calculate the total work, we have;

work = force × distance

force = mass × acceleration

= 70 × 9.81

= 686.7N

Also, distance = speed × time × fractional treadmill grade

∴ distance = 90 meters/min × 10 min ×  0.15 (treadmill grade)

Total work can therefore be calculated as:

work = force × distance

work = 686.7N × (90 meters/min × 10 min × 0.15 (treadmill grade) )

Work = 92,704.5 N/m

Work = 92,704.5 joules

To calculate the power, we have;

Power = workdone/time

Power = 92,704.5 joules/600 seconds

Power = 154.5 joules/second

Power= 154.5 watts

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The percentage of the population that is heterozygous for this trait is 48%

Explanation:

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let the frequency of the dominant allele(A) be p

and the frequency of the recessive allele(a) be q

We are told that 64 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele (that is AA and Aa)

Frequency of AA = p², Frequency of Aa = 2pq and Frequency of aa = q²

Therefore p² + 2pq = 64% = 0.64

According to Hardy–Weinberg:

p² + 2pq + q² = 1 and

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Since p² + 2pq = 0.64

∴ 0.64 + q² = 1

q² = 1 - 0.64 = 0.36

q = √0.36 = 0.6

Since p + q = 1

p = 1 - q = 1 - 0.6 = 0.4

The frequency of heterozygous = 2pq = 2 × 0.4 × 0.6 = 0.48

Therefore the percentage of the population that is heterozygous for this trait is 48%

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