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nadezda [96]
3 years ago
12

A reflection across the x-axis maps the point (4,-5) to the point

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer:

(4,5)

Step-by-step explanation:

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Solve for xxx. Enter the solutions from least to greatest.<br> x^2 + x - 30 = 0x <br> 2<br> +x−30=0
AfilCa [17]

Given:

The quadratic equation is:

x^2+x-30=0

To find:

The solutions of the given equation.

Solution:

We have,

x^2+x-30=0

Splitting the middle term, we get

x^2+6x-5x-30=0

x(x+6)-5(x+6)=0

(x+6)(x-5)=0

Using zero product property, we get

x+6=0 and x-5=0

x=-6 and x=5

Therefore, the solutions of the given quadratic equation are -6 and 5.

6 0
3 years ago
Write the expressions for the following:
musickatia [10]

Answer:

i) (xy)+3 or 3+(xy)

ii) (-2×m)-4

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3 years ago
Read 2 more answers
-4(2x-3) + 4x = 9x -4x +8 -4 answer this
shtirl [24]

Answer:

x = 8/9

Step-by-step explanation:

-4(2x-3) + 4x = 9x -4x +8 -4  

2x*(-4) -3*(-4) + 4x = 9x - 4x  + 8 - 4

-8x + 12 + 4x = 9x - 4x + 8 - 4         {Combine like terms}

-4x + 12 = 5x + 4

12  = 5x + 4x + 4

12 = 9x + 4

12- 4 = 9x

9x = 8

x = 8/9

5 0
3 years ago
Suppose we want to choose 3 objects, without replacement, from the 4 objects pencil, eraser, desk, and chair.
Crank

Answer:

4 ways of choosing

Step-by-step explanation:

If you want to choose 3 objects, without replacement, from the 4 objects which are distinct, then permutation i.e then their arrangement doesn't really matter. Only their combination will be considered

That means, order of choosing doesn't matter,

pencil/ eraser/ desk will be same as  eraser/ desk/ pencil.

Number of ways of selecting 3 objects out of 4 distinct objects is:

⁴C₃ = \frac{4 !}{3! \times (4-3)!}

⁴C₃ = \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1}

⁴C₃ = 4

So, there are 4 ways of choosing

5 0
4 years ago
Which relation is a function? Question 3 options: {(1, 2); (1, 3); (1, 4); (1, 5)} {(1, 2); (2, 3); (3, 4); (4, 5)} {(1, 2); (3,
NeTakaya

To be a function for every identical x value it has to have a different Y value. If the set has two identical X values but they have different Y values it can't be a function.

The set that is a function is:

{(1, 2); (2, 3); (3, 4); (4, 5)}

4 0
3 years ago
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