PLEASE HELP

Use the permutation formula: A church has 10 bells in its bell tower. Before each church service 4 bells are rung in sequence. N

alekssr [168]

Nsiwmalq wk wow a wow. Aka wow aka a snake a

4 0

3 years ago

In the sequence 1, 2, 4, 8, 16, 32, . . . , each term after the first is twice the previous term. What is the sum of the 16th, 1

Leno4ka [110]

Answer:

229376

Step-by-step explanation:

Term n is given by 2ⁿ⁻¹, so the answer is

2¹⁵ + 2¹⁶ + 2¹⁷ = 229376

6 0

3 years ago

A city council is deciding whether or not to spend additional money to reduce the amount of traffic. The council decides that it

garri49 [273]

Answer:

t = 2.9272 > 1.708 at 25 degrees of freedom

null hypothesis is rejected

The council decides that it will increase the transportation budget if the amount of waiting time for drivers is not exceeds 18 minutes

Step-by-step explanation:

Step (i):-

A sample of 26 main roads results in a mean waiting time of 21.1 minutes with a sample standard deviation of 5.4 minutes.

Given sample size 'n' = 26

The mean of the sample 'x⁻ = 21.1 min

Standard deviation of the sample 'S' = 5.4 min

The Population mean 'μ' = 18min

Step(ii):-

Null hypothesis: H₀ : The council decides that it will increase the transportation budget if the amount of waiting time for drivers exceeds 18 minutes.

'μ' > 18min

Alternative hypothesis :H₁:

'μ' <18min

Level of significance : ∝=0.05

Degrees of freedom γ = n-1 = 26-1 =25

The test statistic

$t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }$

$t = \frac{21.1-18}{\frac{5.4}{\sqrt{26} } }$

t = 2.9272

Step(iii):-

The tabulated value t = 1.708 at 25 degrees of freedom

t = 2.9272 > 1.708 at 25 degrees of freedom

Null hypothesis is rejected at 5% significance level of significance

Conclusion:-

The council decides that it will increase the transportation budget if the amount of waiting time for drivers is not exceeds 18 minutes

8 0

3 years ago

PLEASE HELP ME!!! needing help now!

Phoenix [80]

The answer is it should be behind the 7 because you only moved one time in 1.7

7 0

3 years ago

Find an equation of the line that passes through the points (-5, -3) and (3, 1)

Mkey [24]

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-3})\quad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-5)}}}\implies \cfrac{1+3}{3+5}\implies \cfrac{4}{8}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-5)}]\implies y+3=\cfrac{1}{2}(x+5) \\\\\\ y+3=\cfrac{1}{2}x+\cfrac{5}{2}\implies y=\cfrac{1}{2}x+\cfrac{5}{2}-3\implies y = \cfrac{1}{2}x-\cfrac{1}{2}$

6 0

3 years ago

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