PLEASE HELP

Solve for y <br><br> 5y- 10x = 45

nasty-shy [4]

Answer:

y=9 (x=-4.5)

Step-by-step explanation:

you have to split the equation up in order to solve

5y=45

divide by 5 on both sides

y=9

-10x=45

divide by -10

x=-4.5

6 0

3 years ago

The population of Dayton increases by 10% every year. If there are currently 110,000 people living there, what will the populati

MAXImum [283]

You can ask yourself, 110,00 * 10% * 5 years.

4 0

4 years ago

Two angles are complementary. One angle's measure is 3 more than 9

Basile [38]

Answer:

The measure of one angle is 81.3° and the other angle is 8.7°.

Step-by-step explanation:

We are given that two angles are complementary. One angle's measure is 3 more than 9 times the other angle.

Let the measure of one angle be 'x' and the measure of other angle be 'y'.

So, according to the question;

<u>The first condition</u> states that two angles are complementary, this means that the sum of both angles must be equal to 90°, i.e;

x + y = 90°

x = 90° - y ---------------- [equation 1]

The second condition states that One angle's measure is 3 more than 9 times the other angle, i.e;

x = 3 + 9y ------------ [equation 2]

Now, both the equations we get;

90 - y = 3 + 9y

9y + y = 90 - 3

10y = 87

$y=\frac{87}{10}$ = 8.7°

Now, putting the value of y in equation 1 we get;

x = 90° - y

x = 90° - 8.7° = 81.3°

Hence, the measure of one angle is 81.3° and the other angle is 8.7°.

5 0

3 years ago

How do u solve this and what are the answers

iragen [17]

Answer:

7) 7<x<17

8 2.1<x<4.1

9) 0<x<54

10) 7.9<x<35.9

Step-by-step explanation:

you solve by finding the smallest side lengrh which will be the longer length- the shorter, as if the triangle were extremely tiny and all the sides were touching but the third would only be able to be as short as the difference, then for the maximum length as if the triangle were stretches out as much as possible, you add together the lengths because that's the furthest the third could stretch out, remember they will always be less then or greater then, never equal too as well, they can't reach that length other wise it would just be a line

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}

VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

$\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}$

Rationalize the denominator by multiplying both numerator and denominator by √10:

$\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}$

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

$\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}$

8 0

3 years ago