point that lies on the circle is, option C - (4,6)
hope it helps...!!!!
Answer:
5.12 minutes ≈ 5 minutes 7.2 seconds
Step-by-step explanation:
The flight path of the airplane is along the line ...
y = -125/135x = -25/27x
The perpendicular line through Mt. Rainier's location is ...
y = 27/25(x -56) -40
In standard form, these two equations are ...
- 25x +27y = 0
- 27x -25y = 2512
The point of closest approach has the coordinates that are the solution to these two equations:
(x, y) = (33912/677, 31400/677)
The distance d from the origin to this point is given by the Pythagorean theorem (distance formula) as ...
d = 1256√(2/677) . . . . . km
This distance can be converted to time using the speed of the airplane:

5.12 minutes after departing JBLM you will be closest to Mt. Rainier.
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The attached graph shows the geometry of the problem.
I think that your answer would be B) lines that meet at a 90 degree angle. These lines must intersect, and they have slopes that are opposite reciprocals when compared to each other.
Answer:
d.156.
x+24=180 ( being staright angle)
9514 1404 393
Answer:
17) x = 10√2
18) x = 4√6
Step-by-step explanation:
These problems rely on your knowledge of the side ratios of special triangles
45°-45°-90° triangle: 1 : 1 : √2
30°-60°-90° triangle: 1 : √3 : 2
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17) 5 is the short side of the isosceles right triangle, so its hypotenuse is 5√2. That length is the shortest side of the 30/60/90 triangle, so its longest side is 2 times that:
x = 10√2
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18) 8 is the longest side of the 30/60/90 triangle, so its long leg will be 8(√3)/2 = 4√3. The hypotenuse of the isosceles right triangle is √2 times that, so ...
x = (4√3)(√2)
x = 4√6