They would each get 6 dollars and 66 cents :) ♥♥
Answer:
Mr. Abernathy purchased 10 of $1.50 wrenches, 10 of $2.50 wrenches, 5 of $4 wrenches and 6 of $3 wrenches.
Step-by-step explanation:
If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.
<h3>What is mean?</h3>
The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.
On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.
You may compute the weighted mean as follows:
Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.
To learn more about the mean refer;
brainly.com/question/22871228
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Answer:
12.1 cm
Step-by-step explanation:
Using the law of sines, we can find angle C. Then from the sum of angles, we can find angle B. The law of sines again will tell us the length AC.
sin(C)/c = sin(A)/a
C = arcsin((c/a)sin(A)) = arcsin(8.2/13.5·sin(81°)) ≈ 36.86°
Then angle B is ...
B = 180° -A -C = 180° -81° -36.86° = 62.14°
and side b is ...
b/sin(B) = a/sin(A)
b = a·sin(B)/sin(A) = 13.5·sin(62.14°)/sin(81°) ≈ 12.0835
The length of AC is about 12.1 cm.
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<em>Comment on the solution</em>
The problem can also be solved using the law of cosines. The equation is ...
13.5² = 8.2² +b² -2·8.2·b·cos(81°)
This is a quadratic in b. Its solution can be found using the quadratic formula or by completing the square.
b = 8.2·cos(81°) +√(13.5² -8.2² +(8.2·cos(81°))²)
b = 8.2·cos(81°) +√(13.5² -(8.2·sin(81°))²) . . . . . simplified a bit
