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Sonja [21]
4 years ago
5

A swimming pool is to be drained. The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. Su

ppose water is pumped out of the pool at a rate of 216ft3 per hour. If the pool starts completely full, how many hours does it take to empty the pool?
Mathematics
1 answer:
Gala2k [10]4 years ago
8 0

Answer: it will take 9 hours to empty the pool.

Step-by-step explanation:

The pool is shaped like a rectangular prism with length 30 feet, wide 18 ft, and depth 4ft. It means that when the pool is full, its volume is

30 × 18 × 4 = 2160 ft³

If water is pumped out of the pool at a rate of 216ft3 per hour, then the rate at which the water in the pool is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence(initial amount of water in the pool when completely full).

d represents the common difference(rate at which it is being pumped out)

n represents the number of terms(hours) in the sequence.

From the information given,

a = 2160 degrees

d = - 216 ft3

Tn = 0(the final volume would be zero)

We want to determine the number of terms(hours) for which Tn would be zero. Therefore,

0 = 2160 - 216 (n - 1)

2160 = 216(n - 1) = 216n + 216

216n = 2160 - 216

216n = 1944

n = 1944/216

n = 9

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kenny6666 [7]
Bracelet cost = b
Necklace cost = n

15b + 8n = 500
19b + 24n = 980

Elimination method x -3
-45b - 24n = -1500
19b + 24n = 980

-26b = -520
b = $20 bracelets

Plug back in
19(20) + 24n = 980
380 + 24n = 980
24n = 600
n = $25 necklaces


Check:
15(20)+ 8(25)= 500
300 + 200 = 500
500 = 500 :)
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3 years ago
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4 years ago
Sodas in a can are supposed to contain an average 12 oz. This particular brand has a standard deviation of 0.1 oz, with an avera
hoa [83]

Answer:

The probability is  P(X <  12) =  0.99286

Step-by-step explanation:

From the question we are told that

        The population mean is \mu  =  12 \ oz

         The  standard deviation is  \sigma =  0.1 \ oz

          The sample mean is  \= x =  12.1 \ oz

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The standard error of the mean is mathematically represented as

              \sigma_{\= x } =  \frac{\sigma}{\sqrt{n} }

substituting values

            \sigma_{\= x } =  \frac{0.1}{\sqrt{6} }

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Given that the can’s contents follow a Normal distribution then then  the probability that the mean contents of a six-pack are less than 12 oz is mathematically represented as

         P(X <  12) =  P ( \frac{X - \mu }{ \sigma_{\= x }}  < \frac{\= x - \mu }{ \sigma_{\= x }}  )

Generally  \frac{X  - \mu }{ \sigma_{ \= x }}   =  Z (The  \ standardized \  value \ of  \ X )

So

         P(X <  12) =  P ( Z < \frac{\= x - \mu }{ \sigma_{\= x }}  )

substituting values

       P(X <  12) =  P ( Z < \frac{12.2 -12 }{0.0408}  )

      P(X <  12) =  P ( Z < 2.45   )

From the normal distribution table the value of P ( Z < 2.45   ) is  

           P (Z < 2.45)0.99286

=>   P(X <  12) =  0.99286

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