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Nat2105 [25]
3 years ago
6

34.15 round to the nearest hundred

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0
It’s zero, I think. Because
3 doesn’t round up. It’s stays the same. But since there is nothing in the hundred place. It is 0.
You might be interested in
Help please thank you
dimulka [17.4K]

Answer:

i think its 8r^4

hope this helps

Step-by-step explanation:

7 0
3 years ago
There are 10 kids in class. 7 boys and 3 girls. If the teacher were to pick 4 students at random what is the probability of sele
inysia [295]
Well there are 7 boys and 10 students total so 7/10=0.7=70%. Therefore there is a 70% chance.
4 0
4 years ago
1.Give one number that makes the inequality x + 7 > 20 true
nata0808 [166]
1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20

2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25

3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

To find this answer I did 300/16 and got 18.75. You must round to the higher whole <span>number. Rounding down to 18 boxes leaves you with 12 candies without a box.</span>
6 0
3 years ago
Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.
s2008m [1.1K]
Y = -2x + 4
6x + 3y = 6x + 3(-2x + 4) = 6x - 6x + 12 = 12
⇒ y = -2x + 4 == 6x + 3y = 12 ⇒ invinite solutions: 12
⇒ no solutions -12, -4, 0, 4



6 0
4 years ago
PLEASE HELP!!! 20 POINTS!!!
dimulka [17.4K]
18*18=324
16^2+8^2=320=18ish
16^2+18^2=580=22ish
=364
=19.07m^2
6 0
3 years ago
Read 2 more answers
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