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RSB [31]
3 years ago
8

Which formula would be used to find the measure of angle 1?

Mathematics
1 answer:
Stels [109]3 years ago
7 0
What’s angle 1? U need to post a pic
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Is this correct? I tried to solve it on my own haha!
Vladimir [108]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu
irga5000 [103]
We want to find a scalar function f(x,y) such that \nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j.
So we need to have
\dfrac{\partial f}{\partial x}=3+4xy^2
Integrating both sides with respect to x gives
f(x,y)=3x+2x^2y^2+g(y)
Differentiating with respect to y gives
\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C
So we find that
f(x,y)=3x+2x^2y^2+C
By the fundamental theorem of calculus, we then know the line integral depends only on the values of f(x,y) at the endpoints of the path. Therefore

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6
4 0
3 years ago
Math sucks please help me too stupid
asambeis [7]

Answer: with question 1 mark your first line by having it intercept at postive 4 on y axis then count up 1 right 4 then mark a point then mark a point down 1 left 4 then create your line

After that line go to next line but starting at -3 on y axis then go up three left 2 until you cant fit on graph you should get your answer where both lines you draw cross at

Step-by-step explanation:

7 0
3 years ago
Solve the following equation 2/3x+6=1/2x+1/4x
Vanyuwa [196]

Answer:

x= 72

Step-by-step explanation:

combine the Xs on one side and then make the denominators the same and solve

8/12X +6 = 3/4X

sub 6 on both sides

then sub 3/4 (aka. 9/12)

-1/12X= -6

multiply by reciprocal (the fraction flip-flopped)(-12) on both sides

and you get 72

4 0
3 years ago
2^y+1=3x<br> Solve for y.<br> Thank you!
e-lub [12.9K]
Answer; See attachment

7 0
3 years ago
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