What is the area of a regular pentagon with a side length of 9 millimeters and an apothem length of 6.2 millimeters?

1 answer:

4 0

The area of a regular polygon is equal to half of the product of its apothem and perimeter.
A = 0.5aP

Find first the perimeter,
P = 5 x (9 mm)
P = 45 mm

Substituting the perimeter and the apothem to the first equation,
A = 0.5(45 mm)(6.2 mm)
A = 139.5 mm²

Therefore, the area of the regular pentagon is equal to 139.5 mm².

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Caitlin has 4 and 3/4 lb of place use 1 1/10 pound to make a cup and another 2 pounds to make a jar how many pounds are left

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We know that
4 3/4---------> (4*4+3)/4----------> 19/4
1 1/10-----------> (10*1+1)/10----> 11/10

[pounds left]=[(19/4)-(11/10)-(2)]----> (10*19-4*11-40*2)/40
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If the lengths of the legs of a right triangle are 3 and 10−−√, what is the length of the hypotenuse?

Ganezh [65]

The required length of the hypotenuse of the triangle is √19.

<h3>What is a right triangle?</h3>

A right triangle, sometimes known as a right-angled triangle, or more formally an orthogonal triangle, formerly known as a rectangle triangle, is a triangle with one right angle or two perpendicular sides.

To find the required length of the hypotenuse of the triangle:

Legs in the right triangle refer to the perpendicular and base.

Hypotenuse:

$= \sqrt{perpendicular^{2}+base^{2} } \\= \sqrt{3^{2}+\sqrt{10^{2} } } \\=\sqrt{19}$