All categories

3 years ago

Use ≈ 3.14, and round your answer to the nearest hundredth.

Mathematics

1 answer:

DanielleElmas [232]3 years ago

5 0

3. 14 you can't round it it's already rounded

You might be interested in

To factor the trinomial 12x² + 7x - 5, a student must find factors of _____________ that add up to _____________.

inessss [21]

Answer:

factors of -60 that add up to 7

Step-by-step explanation:

3 0

3 years ago

Given the following a=3,b=4, what is the length of side c? 5 6 4

e-lub [12.9K]

Answer:

C=5

Step-by-step explanation:

3^ + 4^2 = 25

and the square root of 25 is 5 therefore C=5

6 0

4 years ago

The mean age of 5 people in a room is 40 years. A person enters the room. The mean age is now 36. What is the age of the person

Igoryamba

Answer:

$\boxed{\sf \ \ \ age = 16 \ \ \ }$

Step-by-step explanation:

Hello,

as the mean age of 5 people is 40

it means that the sum of the 5 ages is 40*5=200

now a person enters the room, let's note x his age

the new mean is

$\dfrac{200+x}{6}=36$

$200+x=6*36=216\\ x = 216-200=16\\$

So the age of the new person is 16

hope this helps

6 0

3 years ago

3 bananas are to be selected from a group of 9. In how many ways can this be done?

lianna [129]

9C3 =9!/((9-3)!3!) =84 ways

7 0

3 years ago

Read 2 more answers

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago

Use ​ ≈ 3.14, and round your answer to the nearest hundredth.

Use ≈ 3.14, and round your answer to the nearest hundredth.