Answer: w= -5.5
Step-by-step explanation: -27.5/5=-5.5. w = -5.5
Answer:
![\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Yes%20%5C%5C%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bf%28x%29%7C-2%20%E2%89%A4%20f%28x%29%20%E2%89%A4%204%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%204%5D%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C0%20%E2%89%A4%20x%20%E2%89%A4%207%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B0%2C%207%5D)
Step-by-step explanation:
Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.
* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.
** This is kind of like a sine wave.
I am joyous to assist you anytime.
Given :
Jack bought 50 lbs of clay for his art projects. He used 13.2 lbs to make a sculpture, and 0.72 lbs for each mug.
To Find :
How many mugs did Jack make if he had 28.88 lbs of clay left over.
Solution :
Clay required to make 1 mug, r = 0.72 lbs.
Amount of clay left after making sculpture is, T = 28.88 lbs.
Now, number of clay mug Jack can make is :

Since, number of mug cannot be in decimal, so we take the floor value.
Therefore, number of mug that can be prepared is 40 .
Answer:
J=-50
Step-by-step explanation:
Answer:
Width = 10 and Length = 16
Step-by-step explanation:
→ Assign variables to the length and width
width = x so length = 6 + x
→ Make an equation
x + 6 + x + x + 6 + x = 52
→ Simplify
4x + 12 = 52
→ Minus 12 from both sides
4x = 40
→ Divide both sides by 10
x = 10
→ Resubstitute into the previously assigned values
width = 10 so length = 16