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Nimfa-mama [501]
3 years ago
14

How do you know that the value of D will decrease when the value of N increases?

Mathematics
1 answer:
zlopas [31]3 years ago
5 0
<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to find good and exact answers. Here I'll assume that you need a relationship between D and N. So we know some facts:

  • As N increases, then D decreases

So this is an inverse relationship. We can write this as:

D\propto \frac{1}{N} \\ \\ \\ \boxed{D=k\frac{1}{N}} \\ \\ \\ \text{Where k is a positive constant}

Since N lies in the denominator, as it increases then D will decrease. So this is a correct relationship

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Solve the system of equations. \begin{aligned} &amp; -10x+3y = 5 \\\\ &amp; x=y-4 \end{aligned} ​ −10x+3y=5 x=y−4 ​
Ksenya-84 [330]

Answer:

x = 1

y = 5

Step-by-step explanation:

You can use either substitution or elimination for this problem. I will use substitution.

Step 1: Replace x in the 1st equation

-10(y-4) + 3y = 5

-10y + 40 + 3y = 5

-7y = -35

y = 5

Step 2: Plug <em>y </em>into an original equation to find <em>x</em>

x = 5 - 4

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And you have your final answers!

7 0
3 years ago
The population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year. A) Estimate how lo
VLD [36.1K]

Answer:

A) 63.36 years.

B) 100.42 years.

Step-by-step explanation:

We have been given that the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year.

A) Since we know that population increases exponentially, therefore we will use our given information to form an exponential model for population increase and then we will solve for the time by which our population will be double.

P(t)=7.1(1.011)^{t}            

7.1 \times 2=7.1(1.011)^{t}  

\frac{7.1 \times 2}{7.1} =(1.011)^{t}

2 =(1.011)^{t}

Now let us solve for t using logarithm.

ln(2) =ln (1.011)^{t}      

ln(2) =t \cdot ln(1.011)

0.6931471805599453 =t \cdot 0.0109399400383344  

t=\frac{0.6931471805599453}{0.0109399400383344}

t=63.3593217267282743049\approx 63.36

Therefore, it will take 63.36 years the population to be double.

B) Now we will find the number of years it will take the population to be triple of its size.

7.1 \times 3=7.1(1.011)^{t}

\frac{7.1 \times 3}{7.1} =(1.011)^{t}  

3 =(1.011)^{t}

Now let us solve for t using logarithm.        

ln(3) =ln (1.011)^{t}

ln(3) =t \cdot ln(1.011)

1.0986122886681097 =t \cdot 0.0109399400383344  

t=\frac{1.0986122886681097}{0.0109399400383344}

t=100.4221490079915311298\approx 100.42

Therefore, it will take 100.42 years the population to triple of its size.


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Step-by-step explanation:

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What i think the answer is 6.66 because u multiply 1/3 by 20 

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