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3 years ago

How do I solve #16? Do I just measure using a protractor or do calculations??

Mathematics

1 answer:

sergejj [24]3 years ago

8 0

For #16, it can be assume that the two angles are linear, so set them both equal to 90 (9x+x-10=90) and solve for x. Once you have x, plug it into the equations to find the measure of both angles. If both your final answers are added, they should equal 180. If not, go back and try to find where you messed up.

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Which rule describes a translation that is 8 units to the right and 2 units up?

Fofino [41]

(x-8, y+2).

When translating figures, a translation to the right subtracts from the x-coordinate (sort of the opposite of how we think of graphs that go to the right). Translations up would be adding to the y-coordinate.

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3 years ago

What effect does the "a" value have on the function f(x)=log(x)

Leni [432]

I would guess they're referring to some general form firstf(x)=alog(x−h)+kWhere 'h' represents horizontal shifts, 'k' vertical shifts and 'a' stretches the function. "a" will also reflect the function across the x-axis if the value is negative. But NOT across the y-axis. I hope that's the place they wanted to put the a at least

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3 years ago

PLS HELP

Fed [463]

12
-4
-8
Those should be the answers

8 0

3 years ago

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If x = -6, which inequality is true?

ziro4ka [17]

Answer:

1-2x>13

Step-by-step explanation:

1-2x>13

-2x>13-1

-2x>12

x>-12/2

x<-6

7 0

3 years ago

1/4(x-2)+4=12 1/4(x-2)=8 x-2=2 x=4 correct the error

konstantin123 [22]

Step-by-step explanation:

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix) = 2

L.H.S. =

By putting m = −6,

L. H. S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(x) = 2

L.H.S. =

By putting m = 0,

L.H.S. = ≠ R.H.S.

∴No, the equation is not satisfied.

(xi) = 2

L.H.S. =

By putting m = 6,

L.H.S. = = R.H.S.

∴ Yes, the equation is satisfied.

8 0

3 years ago

Read 2 more answers