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3 years ago

What are the 3 ratios that are equivalent to 10/16

Mathematics

1 answer:

Sindrei [870]3 years ago

7 0

Answer:

5/8, 15/24, 20/32

Step-by-step explanation:

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Rhonda is downloading a file from the Internet. The size of the file is 7.45 MB. The file is downloading at the rate of 0.095 MB

Rus_ich [418]

Size of file- 7.45 MB.
rate of download- .095 MB a second

7.45/.095=78.42 seconds (a little over a minute)

4 0

4 years ago

9 times the number and 8 is less than or equal to 56

nignag [31]

What do you mean by that?

6 0

4 years ago

Angle M and Angle N are vertical angles. The measure of Angle M is 3x – 18. The measure of Angle N is x + 30.

torisob [31]

Answer:

$24 = x$

$54° = Measure\:of\:Angle\:N$

$54° = Measure\:of\:Angle\:M$

Step-by-step explanation:

Vertical Angles are congruent, so set the two expressions equal to each other:

[x + 30]° = [3x - 18]°

-[3x]° - [3x]°

___________

−18° = 30° - [2x]°

- 30° - 30°

____________

−48° = [−2x]°

____ ___

−2° −2°

$24° = x$ [Plug this back into both expressions to get both m∠N and m∠M at 54°.]

I am joyous to assist you anytime.

5 0

3 years ago

Quadratic Equation

Natasha_Volkova [10]

Step-by-step explanation:

The sum of ages of two friends is 13 years.

The product of their ages is 42.

Let the age of 1st friend and 2nd friend is x, y respectively.

1 st condition= The sum of ages of two friends is 13 yrs.

i.e x+y = 13........ (I)

2nd condition= The product of their ages is 42.

i.e X*y = 42........(ii)

From equation (I)

X+y = 13

or, X = 13-y........ (iii)

Putting the equation (iii) in equation (ii).

X*y= 42

(13-y) * y = 42

13y - y^2 = 42

${y}^{2} - 13y + 42 = 0$

${y}^{2} - (7 + 6)y + 42= 0$

${y}^{2} - 7y - 6y + 42 = 0$

$y(y - 7) - 6(y - 7) = 0$

$(y - 6) (y - 7) = 0$

Either; y-6 = 0

y = 6

Or;

y-7=0

y = 7

Keeping the value of y as "7" in equation (ii)

x*y = 42

7x = 42

X = 42/7

Therefore, the value of X is 6.

Therefore, either 1st friend is 6 years and 2nd is 7 years.

Hope it helps...

7 0

3 years ago

at a small school, one male and one female are selected to represent the student body at the PTSCA meetings. if there are 41 mal

I am Lyosha [343]

It is given that there are 41 males and 48 females in the small school.

So, the number of ways a male student can be chosen from 41 males is $^{41}C_1$

Likewise, the number of ways a female student can be chosen from 48 females is $^{48}C_1$ .

Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:

$^{41}C_1\times ^{48}C_1=1968$

7 0

3 years ago