Answer:
Step-by-step explanation:
If you have an odd number of consecutive numbers, the middle number should be x. So 7 of them would be written as
(x - 3)+(x - 2) + (x - 1) + x + (x + 1) + (x + 2) + (x+3)
That way all you are left with is 7x because the integers cancel.
That is not your question
You question is
Sum = m+(m + 1) + (m + 2) + (m + 3) + (m + 4) + (m + 5) + (m + 6)
We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
Answer:
x=-4
Step-by-step explanation:
Of course not.
-- Take a washable marker, and give your little sister another washable marker.
-- Stand back-to-back in your bedroom, you facing the front wall, and her facing the back wall.
-- When you say 'GO', both of you draw a straight line on the wall.
Then look at the lines.
-- The front and back walls are parallel planes, but it would be
amazing if the two lines are parallel. One could even be a
horizontal line and the other a vertical one . . . definitely not parallel.
I'm pretty sure it would be 118 but I might be wrong