Question

the coordinates of the vertices of triangle ABC are A (1,-1),B (1,4), and C (8,4). what is the length in units of the line segment that connects vertex A and vertex B

Answer 1

ab=

$\sqrt{ (x1 - x2} ) ^{2} + ( y1 - y2 ) ^{2}$

$\sqrt{0 - 25}$

5 unit is length

.

Answer 2

Answer:

AB = 5 units

Step-by-step explanation:

Given that:

• A (1,-1) <=> x1=1 and y1=-1
• B (1,4), <=> x2 = 1 and y2=4
• C (8,4).

So the the length in units of the line segment that connects vertex A and vertex B is the length of line AB. So we have the following formula:

AB = $\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }$

<=> AB = $\sqrt{(1-1)^{2} +(4-(-1))^{2} }$

<=> AB = 5 units

Hope it will find you well.