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d1i1m1o1n [39]
3 years ago
9

the coordinates of the vertices of triangle ABC are A (1,-1),B (1,4), and C (8,4). what is the length in units of the line segme

nt that connects vertex A and vertex B
Mathematics
2 answers:
strojnjashka [21]3 years ago
5 0

ab=

\sqrt{ (x1 - x2} ) ^{2}    +  (  y1 - y2 ) ^{2}

\sqrt{0 - 25}

5 unit is length

.

Bas_tet [7]3 years ago
3 0

Answer:

AB = 5 units

Step-by-step explanation:

Given that:

  • A (1,-1) <=> x1=1 and y1=-1
  • B (1,4), <=> x2 = 1 and y2=4
  • C (8,4).

So the the length in units of the line segment that connects vertex A and vertex B is the length of line AB. So we have the following formula:

AB = \sqrt{(x2-x1)^{2} + (y2-y1)^{2} }

<=> AB = \sqrt{(1-1)^{2} +(4-(-1))^{2}  }

<=> AB = 5 units

Hope it will find you well.

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