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kifflom [539]
3 years ago
11

Factor y2 + 10z - 10y - yz

Mathematics
2 answers:
stira [4]3 years ago
6 0
Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
lara31 [8.8K]3 years ago
5 0
First rearrange the equation.

y2- yz - 10y+ 10z

At this point it's factoring by grouping.
Y(y-z) -10(y-z)
(Y-10)(y-z)
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A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
3 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
In a litter of 7 kittens, each kitten weighs less than 3.5 ounces. Find all the possible values of the combined weights of the k
Dima020 [189]

Let's use w to symbolize the weight of kittens. Given by the statement "each kitten weighs less than 3.5 ounces" we know that

1*w < 3.5

We can multiply both sides of the inequality by 7 to determine the total weights

7*(1*w) < 7*(3.5)

7*w < 24.5

Since there are 7 kittens, the combined weight of the kittens is 7w, therefore the above expression could be read as "The combined weight of the kittens is less than 24.5 ounces"

6 0
3 years ago
laura has a toy robot collection 4/7 of her robots makes noise how many of lauras robots make noise? and can u show ur work pls
ololo11 [35]

Answer:

57 percent

Step-by-step explanation:

4 divided by 7= .57

  •                57 reminder 1
  •             ________
  •          7l 40
  •               35
  •                  50
  •            so the total is 57      
4 0
2 years ago
Amelia has 3 gallons of paint .Mason have 10 quarts .How many more pints of paint does AMELIA have then mason.
Ber [7]

Answer:

4 Pints

Step-by-step explanation:

According to the scenario, calculations are as follows,

As we know, 1 gallon = 8 Pints

1 Quarts = 2 Pints

So, Amelia = 3 Gallons = 3 × 8 Pints = 24 Pints

Mason = 10 quarts = 10 × 2 Pints = 20 Pints

So, Number of more pints Amelia has = Amelia number of pints - Mason number of pints

= 24 pints - 20 pints

= 4 Pints  

6 0
3 years ago
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