Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
Point Form:
(−11,−5/4)
Equation Form:
x=−11,y=−5/4
Greetings!
The best way to compare fractions is to find the LCM (The Lowest Common Denominator) of each of the fractions. This can be done simply by listing the multiples of the denominators.
Multiples:
3: 3,6,9,12,15,18,21,24,27...210,213
10:10,20,30,40,60,70,80...210,220
6: 6,12,18,24,30,36,42,48...210,216
7: 7,14,21,28,35,42,49...210,217
The LCM is 210:
3*70=210
10*21=210
6*35=210
7*30=210
Now, we must do what we do the denominators to the numerators:
1*70=70
70/210
2*21=42
42/210
1*35=35
=35/210
2*30=60
=60/210
The fraction with the largest numerator has the greatest value; In this case it 1/3 or 70/210.
Hope this helps.
-Benjamin
