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2 years ago

8

Lauren woke up one morning and saw frost on the windows. It was -13°C outside. Later in the day, the frost melted. At 3 p.m. it

was 4°C outside. Which expression represents the difference between the two temperatures?

1 answer:

slavikrds [6]2 years ago

8 0

Answer:

morning = -13°C

afternoon = 4°C

so,

x = (morning - afternoon)

I hope this helps a little bit.

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<img src="https://tex.z-dn.net/?f=%5Csqrt%2096" id="TexFormula1" title="\sqrt 96" alt="\sqrt 96" align="absmiddle" class="latex-

klasskru [66]

Answer:

If it is $\sqrt{96} \sqrt{96}$ then it is the solution $\sqrt{96} \sqrt{96} = 96$ because the square root of an expression multiplied by itself gives that expression.

7 0

2 years ago

-1/4b + 1/2 = 5/6<br>Find b

QveST [7]

Answer:

b = -4/3

Step-by-step explanation:

First, subtract the 1/2 over

-1/4b+1/2=5/6

5/6-1/2

To get a common denominator of 6, multipy 1/2 by 3

5/6-1/2(3)

5/6-3/6=2/6

-1/4b=2/6

Next, multiply by the reciprocal of -1/4, or -4

(-4)-1/4b=2/6(-4)

b=-4/3

7 0

3 years ago

Which of these expressions shows a correct way to set up the slope formula for the line that passes through the points (5, 0) an

vaieri [72.5K]

Answer:

C

Step-by-step explanation:

its c because if we input the numbers into the slope formula y2 - y1 over x2 - x1 it equals -6 - 0 over 6 - 5

3 0

3 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

2 years ago

prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample

Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = $\frac{cos \ \theta}{sin \ \theta}$

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ $\frac{cos \ \theta}{sin \ \theta}$

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0

3 years ago