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zhannawk [14.2K]
3 years ago
11

Solve the equation log^7b>2

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is (\log b)^{7} > 2

⇒ \log b > 2^{\frac{1}{7} }

We are taking the base of the log here is 10.

So, 10^{(\log b)} > 10^{2^{\frac{1}{7} } } {Since 10^{\log x} =x and e^{\ln x} = x}

⇒ b > 12.71 (Approximate) (Answer)

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