0.14 I just sent the test
Answer:
(4b-9) (4b+9)
Step-by-step explanation:
16b^2 – 81
This is the difference of squares
(a^2 -c^2) = (a-c) (a+c)
a^2 = 16b^2 so a= 4b
c^2 = 81 so c = 9
(16b^2 – 81) = (4b-9) (4b+9)
Answer:
should be a. took the test and It was horrible. I remember trying and forgot how to do everything beother
Step-by-step explanation:
no balls
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
12 45 785 96
Step-by-step explanation:
