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3 years ago

Which inequality will have a shaded area below the boundary line?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

3x + 4y > 12 <span>will have a shaded area below the boundary line</span>

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Help me, please! For 20 pts

emmasim [6.3K]

Answer:

First box ⇒ 3.6 x 10^-1

Second box ⇒ 3.1 x 10^6

Third box ⇒ 5.3 x 10^-6

Fourth box ⇒ 4.2 x 10^-1

Step-by-step explanation:

I used a calculator and solved it :)

6 0

2 years ago

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a bag contains 1 red beads 2 yellow beads 2 green beads and 1 blue bead a bean is choose and at random what is the probability t

Kisachek [45]

Answer:

Step-by-step explanation:

Add all the beads together to get your total amount of beads (This will be your denominator)

1+2+2+1=6 beads in total

You only want to focus on the amount of green beads. (Which is 2 and that will be you numerator)

$\frac{Numerator}{Demonator}=\frac{green beads}{Total amount of beads}$

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3 years ago

A right triangle with base 3 cm and height 4 cm. What is the hypotenuse

statuscvo [17]

Answer:5

Step-by-step explanation:

3^2+4^2=c^2

9+16=c^2

25=c^2

$\sqrt{25}$ =c

5=c

7 0

3 years ago

Given that 110ₓ = 40₅ , find the value of x.

adell [148]

Answer:

is therr more to that question

Step-by-step explanation:

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4 years ago

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A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c

Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.06, \sigma = 1.1$

$0.06 = 2.575*\frac{1.1}{\sqrt{n}}$

$0.06\sqrt{n} = 2.575*1.1$

$\sqrt{n} = \frac{2.575*1.1}{0.06}$

$(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}$

$n = 2228.6$

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0

3 years ago