(4x-3)(x+5)
= 4x^2+20x-3x-15
= 4x^2+ 17x -15.
The final answer is 4x^2+ 17x -15~
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
The parentheses is:

Square the 6 and the 4:

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:

Therefore:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Answer:
<em><u>z = -3</u></em>
Step-by-step explanation:
<u>Step 1: Simplify both sides of the equation.
</u>
z+7=−z+1
<u>Step 2: Add z to both sides.
</u>
z+7+z=−z+1+z
2z+7=1
<u>Step 3: Subtract 7 from both sides.
</u>
2z+7−7=1−7
2z=−6
<u>Step 4: Divide both sides by 2.
</u>
<u>2z</u> = <u>−6
</u>
2 2
z=−3
The larger one is (-11 + 41)/2 = 15.
The smaller one is (-11 -41)/2 = -26.
_____
For two numbers a and b with sum s and difference d, you can write the equations

Then adding the equations and dividing that sum by 2, you get

You can subtract the second eqution from the first and get a similar result for the smaller number

These are the formulas we used above.
Answer:47m
Step-by-step explanation: