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Alex777 [14]
3 years ago
10

Solve by factoring 7x^2-14x=0

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0
7x²-14x=0
7x²=-14x
sry idk the rest hope this helped a little bit 
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Help me please!!! I give more points and brainliast please help me!
fiasKO [112]

Hey there!!

Fill in the blanks :-

⇒ First graph the line. Locate the <u>value of x </u>on the x-axis. Draw a vertical line from <u>point plotted on the x-axis </u>to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.

<em>Find the value of f(x) when x is -2. </em>

f(x) = \frac{3}{2}x-4

Remember :- <u><em>f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x. </em></u>

Given : x = - 2

Plugging in the values :

... f(-2) = \frac{3*(-2)}{2}-4

... f(-2) = \frac{-3}{1} - 4

... f(-2) = -7

The last fill in the blank :

The value of y on the y-axis is the value of the function. Therefore, the value of f(x) is <u>-7 </u>when x is -2.

Hope it helps!!



7 0
4 years ago
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!
Tamiku [17]
It is a it is symmetric on both sides and it’s peak is at 3
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Shelly ate 4.2 ounces of trail mix. Marshall ate 4.25 ounces of trail mix. How much more trail mix did Marshall eat?
Gekata [30.6K]

Marshall ate 0.05 ounces more

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What is the sum of thirty and twenty
Klio2033 [76]
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4 0
3 years ago
Can anyone solve this
blondinia [14]

Answer:

0

Step-by-step explanation:

Hi! We are given the limit expression:

\displaystyle \large{ \lim_{x \to 2} \frac{x-2}{\sqrt{x^2-4}} }

If we directly substitute x = 2 then we get 0/0 which is an indeterminate form. Therefore, we need to find other methods to evaluate the limit that does not become an indeterminate form.

As for rational function with square root in it, we conjugate the expression by multiplying both denominator and numerator with the square root expression.

\displaystyle \large{ \lim_{x \to 2} \frac{(x-2)(\sqrt{x^2-4})}{\sqrt{x^2-4}\sqrt{x^2-4}} }\\\displaystyle \large{ \lim_{x \to 2} \frac{(x-2)(\sqrt{x^2-4})}{x^2-4} }

When two same square root expressions multiply each other, the square root is taken out as shown above.

From denominator, we can factor x²-4 to (x-2)(x+2) via differences of two squares.

Hence:

\displaystyle \large{ \lim_{x \to 2} \frac{(x-2)(\sqrt{x^2-4})}{(x+2)(x-2)} }

Cancel x-2.

\displaystyle \large{ \lim_{x \to 2} \frac{\sqrt{x^2-4}}{x+2} }

Then substitute x = 2 which we receive 0/4 = 0.

Henceforth, the limit value of expression is 0.

6 0
2 years ago
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