The answer to this question is 492.307
Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
-15/-3 is the awnser hope i helped you
Answer:
5.60 pounds each
Step-by-step explanation:
This is the dry mixture problem.
Let x = the number of pounds of the first type of candy
Therefore, number of pounds of second type of candy = 10-x
Value of first candy + value of second candy = value of mixture
Value of any candy = cost per pound of candy * weight of candy
Thus:
4x + 6(10 - x) = 5.60(10)
4x + 60 - 6x = 56
-2x + 60 = 56
-2x = -4
x = -4/-2
x = 2
Therefore, the number of pounds of first type of candy = 2 pounds
The number of pounds of second type of candy = 10 - 2 = 8 pounds
Check
$4(2) + $6(8) =
8 + 48 = $5.60(10)
$56 = $56
