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Answer:
1. Total spent on transportation $222.2.
2. $ 192.5
3. She spends $30 over the guideline.
Step-by-step explanation:
As per the image attached:
Total monthly spent on transportation = Total monthly car payment + Spent on gas fuel
Total monthly spent on transportation = 120 + 37.9 + 28.4 + 35.9 = $222.2
So, Answer 1. Abby's total spent on transportation = $222.2
Calculating the percentage:
Calculating 11% as per the guideline:
Answer 2. As per the guideline, she should spend $192.5 on transportation.
Difference between spending and guideline = $222.2 - $192.5 = $29.7
Answer 3. She spends $29.7 over the guideline.
Answer:
The mean life of a large shipment of CFL bulbs is equal to 7,520 hours.
Step-by-step explanation:
The quality control manager wants to determine whether the mean life of a large shipment of CFL bulbs is equal to 7,520 hours.
The quality control manager can use a one-sample test to determine whether the mean life is 7,520 hours or not.
The hypothesis can be defined as follows:
<em>H₀</em>: The mean life of a large shipment of CFL bulbs is equal to 7,520 hours, i.e. <em>μ</em> = 7520.
<em>Hₐ</em>: The mean life of a large shipment of CFL bulbs is different from 7,520 hours, i.e. <em>μ</em> ≠ 7520.
The information provided is:
As the population standard deviation is provided, we will use a <em>z</em>-test for single mean.
Compute the test statistic value as follows:
The test statistic value is -1.31.
Decision rule:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected.
Compute the <em>p</em>-value for the two-tailed test as follows:
*Use a <em>z</em>-table for the probability.
The <em>p</em>-value of the test is 0.1902.
The <em>p</em>-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.
Thus, it can be concluded that the mean life of a large shipment of CFL bulbs is equal to 7520 hours.
Answer:
Step-by-step explanation:
<u>Volume And Function s</u>
Geometry can usually be joined with algebra to express volumes as a function of some variable. The volume of a parallelepiped of dimensions a,b,c is
Our problem consists in computing the volume of a box made with some sheet of metal 12 ft by 18 ft. The four corners are cut by a square distance x as shown in the image below .
If the four corners are to be lifted and a box formed, the base of the box will have dimensions (12-2x)(18-2x) and the height will be x. The volume of the box is
Operating and simplifying
