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3 years ago

Which division sentence is related to the product of a/3 (a/3) when A is not equal to 0?

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Answer:

Option 4.

Step-by-step explanation:

Reciprocal of the second fraction turns the product into the division of the two fractions, which equals to 1.

$a/3(a/3)$

$a/3 \div 3/a=1$

Two fractions are said to be the reciprocal or multiplicative inverse of each other, if their product is 1.

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PLEASE HELP. WILL GIVE BRAINIEST AND 60 POINTS if you show work so I can understand these.

Greeley [361]

Answer:

In #1, the slope of the line is 3

Step-by-step explanation:

To find the slope of any line, you need to use the points in the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (5 - 2)/(0 - -1)

m = 3/1

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This means the slope is equal to 3.

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3 years ago

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sesenic [268]

B. Neither/nor is the answer

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Part B

Elza [17]

Answer:

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Step-by-step explanation:

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3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

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