Cosθ = 15/17
Step-by-step explanation:
Sinθ = 8/17
We know that,
Sin^2 θ + cos^2 θ =1
64/289 + cos^2 θ =1
1 - 64/289 = cos^2 θ
225/289 = cos^2 θ
Cos θ = √225/289
Cos θ = 15/17
Answer:
Part 1) The engine speed that maximizes torque is 
Part 2)The maximum torque is 
Step-by-step explanation:
<u><em>The correct equation is</em></u>

This is the equation of a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the engine speed that maximizes torque
The y-coordinate of the vertex represent the maximum torque
Solve the quadratic equation by graphing
using a graphing tool
The vertex is the point (3.093,74.683)
see the attached figure
therefore
The engine speed that maximizes torque is
---> because is in thousands of revolutions per minute
The maximum torque is

Answer:
we have
Cos (a+b)=Cos aCosb-SinaSinb
for
Cos (a+a)=Cos aCosa-SinaSina=<u>Cos²a-Sin²a</u>
is a required answer.
Answer:
8.7 inches rlly hope it helps
Step-by-step explanation: