
<h3>» Ami's mass is

the mass of Raphael.</h3>
<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>
Given that
- Ami's mass is 72 kg and
- Raphael's mass is 108 kg.
To write Ami’s mass as a fraction of Raphael's mass, we divide Ami's mass by Raphael's mass. So it is now
.
However, there the fraction is not yet in its simplest form, so we have to extract common factors from both the numerator and the denominator:
- =

Therefore, Ami's mass is
the mass of Raphael.


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Answer:
Test statistic = 1.818
Reject H0
Step-by-step explanation:
H0 : μ = 90
H1 : μ > 90
xbar = 94 ; s = 22 ; n = 100
The test statistic : (xbar - μ) ÷ (s/√(n))
Test statistic = (94 - 90) ÷ (22/√100)
Test statistic = 4 ÷ 2.2
T = 1.818
The critical value :
At α = 0.10
Degree of freedom = n - 1 = 100 - 1 = 99
Tcritical(0.10, 99) = 1.290
Decison region :
Reject H0 if Test statistic > |Tcritical |
1.818 > 1.290
We reject H0
Add 4x
to both sides of the equation.
a. y=4x+6
Add 5x to both sides of the equation.
b. y=5x+21
It would be C. A perpendicular slope means it has the opposite reciprocal slope, so 1/2 would turn into -2. Since there's only one option with -2 as a slope, C must be right.
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