All categories

3 years ago

A rhombus has sides 10 cm long and an angle of 60°. Find the diagonals of the rhombus.

Mathematics

1 answer:

saul85 [17]3 years ago

8 0

Check the picture below.

recall that in a rhombus the diagonals bisect each other at a right-angle, and that all sides are equal.

thus the longer diagonal is 2a long, and the shorter diagonal is 2b long.

You might be interested in

Whats the best way to do this operation?---------------------------------

SashulF [63]

$400 - $20 = $380 ( The original charge subtract the amount he paid. )
$380 + $18 = $398 (The amount unpaid plus another charge equal total amount unpaid.)
$398 x 0.02 = $7.96 (The amount unpaid multiply the percentage of interest = amount of interest.)

Phillip charged $7.96 interest on his second bill.

5 0

3 years ago

A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect

Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

6 0

4 years ago

jovanna gives a walking tour of a popular tourist city to one person for 34$ to increase her business she would lower the price

exis [7]

She make a tour with 13 people for 30$

8 0

3 years ago

Mrs. Morton has a special reward system for her class. When all her students behave well, she rewards them by putting 3 marbles

Olin [163]

Answer: $24+3r\geq100$

r=26

Step-by-step explanation:

Given: Mrs. Morton rewards her students on behave well by putting 3 marbles into a marble jar.

If the jar contains 24 marbles. and r represent the number of additional times the class is rewarded then the required equation will be

$24+3r\geq100$

If we solve it, we will get the minimum the jar contains 24 marbles.

To solve equation, subtract 24 from both sides, we get

$3r\geq100-24\\\Rightarrow3r\geq76\\\Rightarrow\ r\geq\frac{76}{3}\geq25.333\approx 26$

Hence, the minimum whole number of additional times they need to be rewarded so they can have a party=26

3 0

4 years ago

Read 2 more answers

following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in

valina [46]

Note: As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

Daily expenditure on milk (in Rs) Number of households

0-30 5

30-60 6

60-90 9

90-120 6

120-150 4

Here the maximum frequency is 9.

So, modal class is 60-90.