Answer:
the length of the missing side is 2
Step-by-step explanation:
Use a^2 + b^2 = c^2
a = 4
b = ?
c = 2sqrt5
4^2 + b^2 = (2sqrt5)^2
16 + b^2 = 20
subtract 16 from both sides
b^2 = 4
take the sqrt of both sides
b = 2
A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Answer:
Option A and D
Step-by-step explanation:
straight lines AI, PR, CT intersect each other at a point k.
Opposite or vertical angles are,
1. ∠ AKC and ∠ TKI
2. ∠ IKR and ∠ AKP
Therefore, options (A) and (D) are the correct options.
