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xz_007 [3.2K]
3 years ago
6

Find the image of the given point under the given translation!!!! help please!!!!​

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

P' = (7, - 8)

Step-by-step explanation:

Under the given translation (x + 4, y - 3)

Add 4 to the x- coordinate of P and subtract 3 from the y- coordinate of P

P' = (3 + 4, - 5 - 3 ) = (7, - 8)

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What is the midpoint between (-8, 5) and (2, -2)?
kvasek [131]

Answer: LAST OPTION.

Step-by-step explanation:

For this exercise you need to use the following formula to find the midpoint:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given these points:

(-8, 5)\ and\ (2, -2)

You can identify that:

x_1=-8\\x_2=2\\y_1=5\\y_2=-2

Then, knowing these values, you can substitute them into the formula shown before:

M=(\frac{-8+2}{2},\frac{5+(-2)}{2})

Evaluating, you get that the midpoint is:

M=(-3,1.5)

This matches with the last option.

4 0
3 years ago
If nine is added eighteen times to a number, the result is 173. What is the number?
fomenos

I believe the answer is 19.1 and then you round it from there. Because 173 is not an even number. Check with someone else though. Hope this helps!
3 0
3 years ago
Read 2 more answers
If you plot the distance a train travels as a function of time and get a straight line, you can then find the slope of that line
mezya [45]
The slope ia the Average Speed
3 0
3 years ago
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A scale drawing of a movie screen is 21 inches long and 9 inches tall. The actual screen is 30 feet tall. What is the scale of t
MatroZZZ [7]
<span>A scale factor is the ratio of two similar geometric figures of their corresponding sides. The scale factor is calculated by locating the corresponding sides on each figure. We calculate as follows:

scale factor = 9/30 = 0.3

Hope this answers the question. Have a nice day. </span>
8 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
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