3 years ago

0= (2y-1) (8-y) Let the y = u and y = d be unique solutions to the equation above. What is the value of u ⋅ d?

SAT

1 answer:

mariarad [96]3 years ago

7 0

Answer: The value of u · d = 4

Explanation:

(2y -1) = 0 , 2y = 1 , y = 1/2 . u = 1/2

(8-y)=0 y = 8 d = 8

Substitute values for u·d 1/2 · 8 = 4

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