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netineya [11]
3 years ago
10

What is the slope? y ≥ 1x + 1

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0

y ≥ 1x+1

y ≥ x+1

Two points that are on the graph of y ≥ x+1 are (0,1)and (1,2).

Use the equation for finding the slope.

\frac{y_2-y_1}{x_2-x_1}

\frac{2-1}{1-0}=\frac{1}{1}=1

The slope is 1.

Varvara68 [4.7K]3 years ago
4 0

Note the equation (the equal sign can be replaced by any other sign (greater than, less than, etc).

y = mx + b

y = y

x = x

m = slope

b = y-intercept

----------------------------------------------------------------------------------------------------------

In this case, 1 is in the place of m, therefore, 1 is the slope.

1 is your answer

~

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Anuta_ua [19.1K]

<em>Answer:</em>

<em></em>\boxed{x \leq -16}<em></em>

<em>Step-by-step explanation:</em>

<em></em>(-\frac{3}{4})^{(x)} \geq 12<em></em>

<em>Simplify both sides of the inequality.</em>

<em></em>\frac{-3}{4} x \geq 12<em></em>

<em>Multiply both sides by 4/(-3).</em>

<em></em>(\frac{4}{-3}) * (\frac{-3}{4}x) \geq  (\frac{4}{-3}) * (12)<em></em>

<em></em>= x \leq -16<em></em>

<em>Hope this helped you!</em>

8 0
3 years ago
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Anon25 [30]

Answer:

Routine: started doing his homework.

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Step-by-step explanation:

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Answer: Third option.

Step-by-step explanation:

To solve this exercise it is important to remember the following:

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Then, given the following expression provided in the exercise:

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You need to distribute the postive sign:

8.4x+2.9-3.7x+5

And finally, you must add the like terms:

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6 0
3 years ago
Construct a circle of any radius, and draw a chord on it. Then construct the radius of the circle that bisects the chord. Measur
Nady [450]

Answer:

Part A: See the image attached. The angle between the radius and the chord will always be 90 degree if the radius is perpendicular to the chord

Part B: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

We know that ΔAEC≅AED by SSS criteria (SSS criteria is when all three sides of a triangle is equal making them congruent)

to prove this that they apply to the SSS criteria:

m∠ADO=m∠BDO

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Part C: See the image attached. A radius is perpendicular to a chord when the chord is equally divided in half by the radius.

Part D: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

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OD≅OD by reflexive theorem

ΔADO≅ΔBDO because they are both right triangle with the hypotenuse and a side

AB≅BC means that OC is perpendicular to AB

If you are still confused then I recommend watching these vdos by khan academy about proving perpendicular radius bisector: https://youtu.be/2NgzruZ4_5c

https://youtu.be/TgDk06Qayxw

Hope this helped bye:)

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