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2 years ago

Click on the length of the rectangle

Mathematics

1 answer:

umka2103 [35]2 years ago

7 0

Answer:

It's 2 1/4

Step-by-step explanation:

I dont know how to explain this... but I'm 100% positive on the answer so

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sergeinik [125]

Answer:

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Step-by-step explanation:

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3 years ago

Mr w is 5 times as old as his son Liam and Liam is two years older than his brother Jake, if the combined age of alk the Wiggins

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adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

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2 years ago

Two ways to simplify 2(5ft + 3ft)

strojnjashka [21]

Either you can use distributive property or you can add up the numbers in the brackets.
Hopefully that helped! :)

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3 years ago

Which of the following is INCORRECT? *

DedPeter [7]

this option is incorrect

A straight angle is one full revolution.

Step-by-step explanation:

Straight angle = 180°

Angle take 360° in one revolution

6 0

2 years ago

Click on the length of the rectangle​

Click on the length of the rectangle