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3 years ago

What relation does not have an initial value of 50

1 answer:

4 0

I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

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The weight of a box varies directly as the volume of the box. If a 138-pound box has a volume of 23 gallons, what is the weight

kolezko [41]

Answer:

D. 150 pounds

Step-by-step explanation:

For be directly proportional, it has to be that as one value increases the other does it equally, so

If 138 pound box has a volume of 23 gallons for 25 gallons ?. For being directly proportional tha value must be higest

138 → 23 $x=\frac{25*138}{23} = 150$

x → 25

5 0

2 years ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

2 years ago

PLEASE HELP!!! I'LL MARK AS BRAINLIEST TO THE FIRST PERSON THAT CAN ANSWER!!!

Alisiya [41]

The product of powers property.

5 0

1 year ago

A total of 150 students have taken an Algebra 2 final exam. The scores are normally distributed with a mean of 71% and standard

WARRIOR [948]

Answer:

102 students

Step-by-step explanation:

Note that 65% and 71% are both 1 standard deviation from the mean (71%). According to the empirical rule, 68% of scores lie within 1 std. dev. of the mean.

68% of 150 students would be 0.68(150 students) = 102 students

3 0

2 years ago

What is 20 percent of 240???

Charra [1.4K]

$20\% \ of \ 240= \frac{20}{100}*240= \\\\ =20*2.4=\\\\=\boxed{48}$

5 0

2 years ago

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