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kap26 [50]
4 years ago
9

Find the sum of the finite geometric series -3+6-12+24+-48+96-192+384

Mathematics
1 answer:
hammer [34]4 years ago
3 0
255 (hope this helped)
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Contains (7,2) and is parallel to the graph of 5x-3y=6
dezoksy [38]
(y - 2) = (5/3)(x - 7) Is horizontal and contains.


I'm not sure that's the answer but I hope it helps you with something!!
7 0
4 years ago
PLS help meeeeeeee!!!!!! will mark as BRAINLIEST
Zolol [24]

We are asked to find 7 is what percent to 30.

We will use proportions to solve our given problem.      

Let us assume that 7 is n% of 30. So we can set a proportion as:

\frac{n}{100}=\frac{7}{30}

Let us solve for n.

\frac{n}{100}\cdot 100=\frac{7}{30}\cdot 100

n=\frac{7}{3}\cdot 10

n=\frac{70}{3}

n=23.333

Therefore, 7 is 23.333\% of 30.

3 0
3 years ago
Solve for p, I don't know what else to add but yeah<br> solve for p?<br> Also explain
Charra [1.4K]

Answer:7

Step-by-step explanation:

6p-4+7p+3=90

13p-1=90

13p=91

p=7

4 0
3 years ago
Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


6 0
3 years ago
6(p+3)-6(p+5) expand and simplify need help asap
Alex Ar [27]

Step-by-step explanation:

6(p+3)-6(p+5)=6p+18-6p-30=-12

8 0
3 years ago
Read 2 more answers
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