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katen-ka-za [31]
4 years ago
11

Write an equation in point-slope form for each line (If possible please show work)

Mathematics
1 answer:
kompoz [17]4 years ago
7 0

Hey there! :)

Answer:

x = 1/2(y -3)

Step-by-step explanation:

Begin by finding the slope using the slope formula:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

Plug in the coordinates:

m = \frac{4-3}{2-0}

Simplify:

m = \frac{1}{2}

Recall that point-slope form is:

(x-x_{1}) = m(y-y_{1})

Plug in the slope and coordinates into the equation:

(x - 0) = 1/2(y - 3)

x = 1/2(y -3)

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B. A polygon is either a square or a rectangle
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3 years ago
(5x2 + 4x + 3) - (2x2 - 2x + 5)
Setler [38]

Answer:

3x^2+6x-2

Step-by-step explanation:

(5x2 + 4x + 3) - (2x2 - 2x + 5)

5x^2+4x+3-2x^2+2x-5

3x^2+6x-2

7 0
3 years ago
What is the solution of the system? Use the elimination method. 2x+y=206x−5y=12 Enter your answer in the boxes.
astraxan [27]

Answer:

The answer to your question is:   x = 7; y = 6

Step-by-step explanation:

                                             2x+y=20             ( 1 )  Multiply by 5

                                             6x−5y=12            ( 2 )

                               5 (2x+y=20)    = 10x + 5y = 100

                                          10x + 5y = 100

                                            6x − 5y =   12             Eliminate y

                                          16 x        = 112

                                           x = 112 / 16

                                           x = 7

                                 2(7) + y = 20                 Substitution

                                 14 + y = 20

                                 y = 20 - 14

                                 y = 6

7 0
4 years ago
Which of the following is the quotient of b and a?
vlabodo [156]
\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\


\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
\\\\\\
\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}
5 0
3 years ago
~.❤~Please Answer~❤.~
lord [1]

Answer:

a,b

Step-by-step explanation:

5 0
3 years ago
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