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Fudgin [204]
3 years ago
6

He was Georgia's first royal governor, serving from 1754-1757, but his style of command angered many colonists and led to his re

call in 1757.
Social Studies
2 answers:
Elena-2011 [213]3 years ago
6 0
I think it is John Reynolds.. Hope this helps
dusya [7]3 years ago
3 0

Hi!

<u>John Reynolds</u> was the first royal governor that served from 1754 to 1757.

Reynolds was a British man appointed to rule in Georgia, but his council became very agitated because of his leadership style. <u>By 1757, Reynolds was voted off and was sent back to England</u>.

To replace him, the board sent lieutenant governor, Henry Ellis.

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The first dictator of the Roman empire was Titus Lartius Flavus and he was appointed in 501 BC.
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A writer for a company headquartered in Texas is designing a 100 page report, the text ofwhich must be single-spaced to minimize
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Hi! The answer to your question would be option B.

Explanation:

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Question 1(Multiple Choice Worth 5 points)
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Answer:

The correct answer is d) Supply.

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3 years ago
if a woman in a plane waiting to parachute is 3,940m high and has a mass of 70kg,what is her gravitational potential energy (gpa
LiRa [457]

Answer:

\boxed {\boxed {\sf 2,702,840 \ Joules }}

Explanation:

The gravitational potential energy can be found using the following formula

E_p=m*g*h

Where <em>m</em>= mass, <em>g</em>= gravitational acceleration, and <em>h </em>= height.

We know the the mass of the woman is 70 kilograms and the height is 3,940 meters

If we assume this parachute is on Earth, then the gravitational acceleration is 9.8 m/s²

m= 70 \ kg \\h= 3,940 \ m \\g= 9.8 \ m/s^2

Substitute the values into the formula.

E_p= (70 \ kg) (9.8 \ m/s^2)(3,940 \ m)

Multiply the first two numbers first.

E_p=686 \ kg*m/s^2 (3,940 \ m )

  • 1 kg*m/s² is equal to 1 Newton. Therefore, the first number (686 kg*m/s²) is also equal to 686 Newtons

E_p=686 \ N (3,940 \ m)

Multiply again.

E_p= 2702840 \ N*m

  • 1 Newton meter is equal to 1 Joule. So, our answer of 2702840 N*m is equal to 2702840 J

E_p=2702840 \ J

The potential energy of the women is<u> 2,702,840 Joules </u>

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